APPLICATION OF ALGEBRA
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Subject: Additional Mathematics
Class: SHS 2
Term: 1st Term
Week: 1
Grade code: 2.1.1.LI.2
Strand code: 1
Sub-strand code: 1
Content standard code: 2.1.1.CS.1
Indicator code: 2.1.1.LI.2
Theme: MODELLING WITH ALGEBRA
Subtheme: APPLICATION OF ALGEBRA
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This lesson explores the practical application of Set Theory. While we often think of algebra as just 'x' and 'y', set theory is a powerful algebraic tool for organising, grouping, and solving complex problems in the real world. In Ghana, from a market woman sorting her goods, to a company analysing customer data, to a football coach selecting a team, the principles of sets are used every day, often without us realising it. This lesson will equip learners with the skills to formally model and solve these real-world problems using the language and laws of sets. We will move beyond basic diagrams to use set algebra as a problem-solving tool.
This section serves as both a review and an extension of set theory concepts. 2.1 Foundational Concepts (Review) Set: A well-defined collection of distinct objects or elements. E.g., The set of subjects you are studying, `S = {Maths, English, Science, Social Studies}`. Universal Set (U): The set containing all possible elements under consideration in a particular problem. E.g., If we are discussing students in SHS2, the Universal Set is `U = {all students in SHS2}`. Subset (⊂): A set A is a subset of set B if every element of A is also in B. Union (A ∪ B): The set of all elements that are in A, or in B, or in both. The keyword is "OR". Intersection (A ∩ B): The set of all elements that are in both A and B. The keyword is "AND". Complement (A' or Aᶜ): The set of all elements in the universal set (U) that are not in A. Cardinality of a Set (n(A)): The number of elements in a set A. E.g., If `A = {a, b, c}`, then `n(A) = 3`. 2.2 The Principle of Inclusion-Exclusion
This is the fundamental formula for solving problems involving the number of elements in combined sets.
For Two Sets: The number of elements in the union of two sets A and B is: `n(A ∪ B) = n(A) + n(B) - n(A ∩ B)` Reasoning: When we add `n(A)` and `n(B)`, we count the elements in the intersection (`A ∩ B`) twice. Therefore, we must subtract it once.
For Three Sets: The formula for three sets A, B, and C is: `n(A ∪ B ∪ C) = n(A) + n(B) + n(C) - n(A ∩ B) - n(A ∩ C) - n(B ∩ C) + n(A ∩ B ∩ C)` Reasoning: We add the three sets, subtract the three pairs of intersections (which were double-counted), and then add back the central intersection (`A ∩ B ∩ C`) because it was added three times and then subtracted three times. 2.3 Laws of Set Algebra