Lesson Notes By Weeks and Term v4 - SHS 2

MAKING PREDICTIONS WITH DATA

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Subject: Additional Mathematics

Class: SHS 2

Term: 2nd Term

Week: 19

Grade code: 2.4.2.LI.2

Strand code: 4

Sub-strand code: 2

Content standard code: 2.4.2.CS.2

Indicator code: 2.4.2.LI.2

Theme: HANDLING DATA

Subtheme: MAKING PREDICTIONS WITH DATA

Lesson Video

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Performance objectives

Lesson summary

In Ghana, we see arrangements everywhere. Think about how a market woman arranges different fruits in a row to attract customers, how students are seated for an examination, or how the national football team lines up before a match. In all these situations, the order in which things are placed is important. A change in the order creates a completely new arrangement. Permutations are the mathematical tool we use to count these arrangements. Understanding permutations helps us solve problems in scheduling, coding, security (like PINs and passwords), and even in planning events.

Lesson notes

Concept 1: What is a Permutation?

A permutation is an arrangement of objects in a specific order. The key phrase here is specific order. If the order changes, it becomes a different permutation. Example: Consider the letters A, B, and C. Arranging two letters at a time, we get: AB, BA, AC, CA, BC, CB. Notice that AB is different from BA. The order matters. There are 6 possible permutations (arrangements) of 2 letters chosen from the 3 available letters. Concept 2: Factorial Notation (!)

Before we can calculate complex permutations, we need to understand factorials. The factorial of a non-negative integer 'n', denoted by n!, is the product of all positive integers less than or equal to n. Formula: `n! = n × (n-1) × (n-2) × ... × 3 × 2 × 1` Examples: `4! = 4 × 3 × 2 × 1 = 24` `6! = 6 × 5 × 4 × 3 × 2 × 1 = 720` Special Case: By definition, `0! = 1`. This is important for our formulas to work correctly. Concept 3: Permutations of 'n' distinct objects taken 'r' at a time (nPr)

This is the most common type of permutation problem. It answers the question: "From a group of 'n' different items, how many ways can we choose and arrange 'r' of them?" Formula: `nPr = n! / (n - r)!` Where: 'n' is the total number of objects available. 'r' is the number of objects we are selecting and arranging.

Evaluation guide