Lesson Notes By Weeks and Term v5 - Grade 12

Revision and examination preparation (Grade 12 Mechanical Technology) – Week 10 focus

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Subject: Mechanical Technology

Class: Grade 12

Term: Term 4

Week: 10

Theme: General lesson support

Lesson Video

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Performance objectives

Lesson summary

This week marks a critical stage in your Grade 12 Mechanical Technology journey – focused revision and examination preparation. It's not just about memorizing facts; it's about consolidating your understanding of the year's content and applying it effectively to solve problems. Mechanical Technology provides crucial skills and knowledge relevant to South Africa's industrial and manufacturing sectors. From maintaining mining equipment to designing solutions for our infrastructure challenges, the principles you've learned are directly applicable. Proper revision now will ensure you are well-prepared to contribute to these sectors upon completion of your studies.

Lesson notes

This week, we will revisit the key topics you've covered throughout the year. Instead of simply re-teaching each topic, we will focus on identifying common pitfalls in exam questions and strategies for effective responses. 2.1 Fitting and Machining: Tolerances and Fits: Understanding tolerances (limits of acceptable variation) and fits (degree of tightness/looseness between mating parts) is crucial. Exam questions often require you to calculate clearances or interferences based on given dimensions and tolerances. Remember to always state the units of your answer (e.g., mm). A common mistake is not converting all dimensions to the same unit before calculating.

Example: A hole is specified as 25.00 mm +0.02 mm / -0.00 mm. A shaft is specified as 24.98 mm +0.00 mm / -0.01 mm. Calculate the maximum and minimum clearance.

Solution: Maximum hole size: 25.00 + 0.02 = 25.02 mm Minimum hole size: 25.00 - 0.00 = 25.00 mm Maximum shaft size: 24.98 + 0.00 = 24.98 mm Minimum shaft size: 24.98 - 0.01 = 24.97 mm Maximum Clearance: Max Hole - Min Shaft = 25.02 - 24.97 = 0.05 mm Minimum Clearance: Min Hole - Max Shaft = 25.00 - 24.98 = 0.02 mm Machining Processes: Be familiar with various machining operations like turning, milling, drilling, and grinding. Exam questions may ask you to describe the process, identify suitable cutting tools, or explain safety precautions. Remember to be specific in your descriptions, mentioning key parameters like cutting speed, feed rate, and depth of cut.

Tool Geometry: Understand the angles and their effects on machining performance. Incorrect tool geometry can lead to poor surface finish, tool wear, and even tool breakage. 2.2 Systems and Control (Mechanisms): Gear Ratios: Problems involving gears are common.

Remember the formula: Gear Ratio = Number of Teeth on Driven Gear / Number of Teeth on Driving Gear = Speed of Driving Gear / Speed of Driven Gear. Be careful with compound gear trains; you need to calculate the overall gear ratio by multiplying the ratios of each pair of meshing gears.

Example: A motor with a speed of 1440 RPM drives a shaft through a 20-tooth gear meshing with an 80-tooth gear. Calculate the speed of the shaft.

Solution: Gear Ratio = 80 / 20 = 4 Shaft Speed = Motor Speed / Gear Ratio = 1440 / 4 = 360 RPM Levers: Identify the fulcrum, effort, and load. Apply the principle of moments (Effort x Effort Distance = Load x Load Distance) to solve problems. Be mindful of the units (e.g., Nm).

Pulleys and Belts: Similar to gears, calculate velocity ratios and driven speeds. Consider slip in belt drives, which reduces the effective velocity ratio.

Cams and Followers: Understand the different types of cam profiles (e.g., harmonic, constant velocity) and their effects on follower motion. Be able to sketch displacement diagrams. 2.3 Hydraulics and Pneumatics: Pascal's Law: Pressure applied to a confined fluid is transmitted equally in all directions.

Use the formula: Pressure = Force / Area. Exam questions often involve calculating forces and pressures in hydraulic or pneumatic systems.

Example: A hydraulic cylinder has a piston area of 0.01 m². If the pressure in the cylinder is 5 MPa, calculate the force exerted by the piston.

Solution: Pressure = 5 MPa = 5 x 10^6 Pa Force = Pressure x Area = (5 x 10^6) x 0.01 = 50,000 N = 50 kN Hydraulic Circuits: Be able to interpret hydraulic circuit diagrams and explain the function of various components like pumps, valves, and actuators. Focus on understanding the direction of fluid flow and how valves control the system's operation.

Pneumatic Systems: Similar to hydraulics, understand the components and their functions in pneumatic circuits. 2.4 Materials: Properties of Materials: Understand the key mechanical properties of materials like tensile strength, yield strength, hardness, toughness, and ductility. Relate these properties to the suitability of materials for specific applications. For example, high tensile strength is important for structural components, while high wear resistance is important for cutting tools.

Heat Treatment: Know the different heat treatment processes (e.g., annealing, hardening, tempering) and their effects on the properties of steel. Be able to explain the reasons for using each process. Guided Practice (With Solutions)

Question 1: A spur gear with 36 teeth is meshed with another spur gear with 72 teeth. The first gear rotates at 60 rpm. (a) Calculate the gear ratio. (b) Calculate the rotational speed of the second gear.

Solution: (a) Gear Ratio = Number of Teeth on Driven Gear / Number of Teeth on Driving Gear = 72 / 36 = 2 (b) Gear Ratio = Speed of Driving Gear / Speed of Driven Gear. 2 = 60 / Speed of Driven Gear Speed of Driven Gear = 60 / 2 = 30 rpm

Commentary: This question tests your understanding of gear ratios and their relationship to rotational speeds. Ensure you correctly identify the driving and driven gears.

Question 2: A hydraulic press has a piston with a diameter of 100 mm.