Lesson Notes By Weeks and Term v5 - Grade 12

Integrated exam preparation using mixed real-life tasks – Week 7 focus

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Subject: Mathematical Literacy

Class: Grade 12

Term: Term 4

Week: 7

Theme: General lesson support

Lesson Video

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Performance objectives

Lesson summary

This week, we're diving deep into integrated exam preparation using mixed real-life tasks. This isn't just about passing the Matric exam; it's about developing the critical thinking and problem-solving skills you'll need to navigate everyday situations in South Africa. From budgeting your income to understanding loan repayments and interpreting data related to crime statistics, Mathematical Literacy equips you to be an informed and empowered citizen. Many tasks in real life require you to integrate knowledge from different areas of maths – hence, this week's focus. This week, we'll consolidate our knowledge and build confidence by tackling complex, multifaceted problems.

Lesson notes

This week's focus is on integrating different mathematical literacy skills to solve real-world problems. This means combining concepts from various sections of the CAPS curriculum within a single scenario. Let's review some key areas and demonstrate how they often interlink: 2.1 Financial Mathematics: Simple and Compound Interest: Understanding how interest accrues on savings and loans is fundamental. Simple interest is calculated only on the principal amount, while compound interest is calculated on the principal and any accumulated interest.

Simple Interest:* A = P(1 + rt), where A is the final amount, P is the principal, r is the interest rate, and t is the time in years.

Compound Interest:* A = P(1 + r/n)^(nt), where n is the number of times interest is compounded per year.

Inflation: The rate at which the general level of prices for goods and services is rising, and consequently, the purchasing power of currency is falling. Future Value = Present Value x (1 + Inflation Rate)^Number of Years Budgeting: Creating a plan for how to spend your money, ensuring expenses are covered. This often involves calculating income, expenses (fixed and variable), and savings goals.

Loans and Mortgages: Understanding loan terms, interest rates, and repayment schedules. Amortization schedules show how each payment is divided between principal and interest.

Taxation: Calculating income tax based on taxable income and applicable tax brackets in South Africa. This includes understanding deductions and rebates.

Example 1: Loan Repayment Simphiwe wants to buy a car for R150,

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0. He takes out a loan at an interest rate of 12% per annum, compounded monthly, over 5 years. (a) Calculate the monthly repayment. (b) Calculate the total amount Simphiwe will repay over the 5 years. (c) How much interest will Simphiwe pay in total?

Solution: (a)

We use the loan repayment formula: M = P [i(1+i)^n] / [(1+i)^n - 1] Where: M = Monthly payment P = Principal amount (R150,000) i = Monthly interest rate (12%/12 = 0.01) n = Total number of payments (5 years * 12 months/year = 60) M = 150000 [0.01(1+0.01)^60] / [(1+0.01)^60 - 1] M = 150000 [0.01(1.01)^60] / [(1.01)^60 - 1] M = 150000 [0.01(1.8167)] / [1.8167 - 1] M = 150000 [0.018167] / [0.8167] M = 2725.05 / 0.8167 M = R3336.61 (Rounded to 2 decimal places) Therefore, Simphiwe's monthly repayment is R3336.61. (b) Total amount repaid = Monthly payment * Number of payments Total amount repaid = R3336.61 * 60 = R200196.60 (c) Total interest paid = Total amount repaid - Principal amount Total interest paid = R200196.60 - R150000 = R50196.60 Simphiwe will pay R50196.60 in interest. 2.2 Measurement and Conversions: Units of Measurement: Understanding metric and imperial units and converting between them (e.g., meters to feet, kilograms to pounds, liters to gallons). Knowing South African standard units is crucial. Area, Volume, and Perimeter: Calculating these for various shapes (rectangles, triangles, circles, cylinders, etc.).

Scale Drawings and Maps: Interpreting and using scales to determine actual distances and sizes.

Example 2: Building a Garden Zanele wants to build a rectangular vegetable garden. She wants the garden to have an area of 12 square meters. She also wants to fence the entire garden. She has 14 meters of fencing available. (a) Determine possible dimensions (length and width) of the garden. (b) Which dimensions would minimize the amount of fencing used (i.e., have the smallest perimeter)?

Solution: (a) Area = Length x Width = 12 m² Possible dimensions: Length = 6m, Width = 2m Length = 4m, Width = 3m Length = 12m, Width = 1m (b) Perimeter = 2(Length + Width)

For 6m x 2m: Perimeter = 2(6+2) = 16m (This option is invalid as it exceeds the 14m of fencing)

For 4m x 3m: Perimeter = 2(4+3) = 14m For 12m x 1m: Perimeter = 2(12+1) = 26m (This option is invalid as it exceeds the 14m of fencing) Therefore, the dimensions that minimize the amount of fencing used are 4m x 3m. 2.3 Data Handling: Data Collection and Organization: Gathering data and presenting it in tables, charts, and graphs.

Measures of Central Tendency: Calculating mean, median, and mode to describe data sets.

Measures of Dispersion: Calculating range, interquartile range (IQR), and standard deviation to understand data variability.

Probability: Understanding the likelihood of events occurring.

Interpreting Graphs and Charts: Analyzing different types of graphs (bar graphs, pie charts, line graphs, histograms) to draw conclusions.

Example 3: Crime Statistics A table shows the number of reported burglaries in a neighborhood over the past 5 years: | Year | Number of Burglaries | |---|---| | 2019 | 52 | | 2020 | 45 | | 2021 | 38 | | 2022 | 42 | | 2023 | 35 | (a) Calculate the mean number of burglaries per year. (b) Calculate the percentage decrease in burglaries from 2019 to 2023. (c) Based on this data, what conclusions can you draw about crime trends in the neighborhood?